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Derivative of f(t)=1/t^2(csct-4)

(Can someone show me step by step with an explanation? My prof seriously doesn’t know how to teach and I’m really confused)

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Explanation:

f(t) = (1/t²) (csc t − 4)

Rewrite 1/t² using negative exponents:

f(t) = t⁻² (csc t − 4)

To take the derivative, you'll need three derivative rules:

Power rule:

d/dx (xⁿ) = n xⁿ⁻¹

Product rule:

d/dx (f(x) g(x)) = f'(x) g(x) + f(x) g'(x)

Derivative of cosecant:

d/dx (csc x) = -csc x cot x

We'll start by applying product rule:

f'(t) = d/dt (t⁻²) (csc t − 4) + t⁻² d/dt (csc t − 4)

Next we apply power rule:

f'(t) = (-2 t⁻³) (csc t − 4) + t⁻² d/dt (csc t − 4)

Finally, we use derivative of cosecant:

f'(t) = (-2 t⁻³) (csc t − 4) + t⁻² (-csc t cot t)

Simplifying:

f'(t) = -2 t⁻³ (csc t − 4) − t⁻² csc t cot t

f'(t) = -t⁻³ (2 (csc t − 4) + t csc t cot t)

f'(t) = -t⁻³ (2 csc t − 8 + t csc t cot t)

f'(t) = -(2 csc t − 8 + t csc t cot t) / t³

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