Question

What is the equation of a line that is perpendicular to y

= 4x + 6 and it passes through the point (8, 12)

Answer 1

the equation of a line given two points, a slope, or intercept step-by-step. ...$\mathrm{Perpendicular\:to\:}y=4x+6\mathrm{,\:and\:passing\:through\:}\left(-8 ... Find the line y = mx + b perpendicular to y =4 x +6 that passes through (−8, 10).

Explanation:

Answer 2

y = -1/4x + 14

Explanation:

Perpendicular lines have opposite reciprocal slopes, so the line's slope will be -1/4

Plug in the slope and given point into y = mx + b to find b

y = mx + b

12 = -1/4(8) + b

12 = -2 + b

14 = b

Then, plug in the slope and b into the equation again

y = -1/4x + 14 will be the equation