Answer:
B
Step-by-step explanation:
you will have to find the number of moles for each 4Nh3 and 3cl2
4NH3
m= 1.63
mr= 14+1x3= 17
n.of moles = 1.63/17=0.09588
3CL2
m=3.47
mr=35.5x2=71
nof moles = 3.47/71= 0.04887
after getting the number of moles you will divide your answer by its ratio
4NH3 3CL2
0.09588/4=0.02397 0.04887/3= 0.0133
the smaller number will be the limiting reagent while the bigger number is the excess reagent