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Somebody please help me with this problem.

Somebody please help me with this problem.-example-1

1 Answer

1 vote

Answer:


\bold{p=\frac{2SA-2B}l}

Explanation:


\bold{SA=\frac12lp+B}\\-B\qquad-B\\\\\bold{SA-B=\frac12lp}\\{}\qquad^(*2)\qquad^(*2)\\\\\bold{2SA-2B=lp}\\{}\qquad/ l\qquad/ l\\\\\bold{(2SA-2B)/(l)=p}

User Eburgos
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