Question

How many grams of oxygen are needed to

react with 425 grams of magnesium to

produce 600 grams of magnesium oxide?

Gaman ond withians

Answer 1

Step-by-step explanation:

2Ma+O2 ---- 2MaO

mass of Mg +Mass pf O2 = Mass of MgO

(conservation of mass )

425 + X =600

so the mass of O2 = 600-425 = 175 g

Answer 2

283.33 g of O2.

Step-by-step explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2Mg + O2 —> 2MgO

Next, we shall determine the masses of Mg and O2 that reacted together from the balanced equation. This can be obtained as follow:

Molar mass of Mg = 24 g/mol

Mass of Mg from the balanced equation = 2 × 24 = 48 g

Molar mass of O2 = 16 × 2 = 32 g/mol

Mass of O2 from the balanced equation = 1 × 32 = 32 g

From the balanced equation above,

48 g of Mg reacted with 32 g of O2.

Finally, we shall determine the mass of O2 needed to react with 425 g of Mg as follow:

From the balanced equation above,

48 g of Mg reacted with 32 g of O2.

Therefore, 425 g of Mg will react with = (425 × 32)/48 = 283.33 g of O2.

Therefore, 283.33 g of O2 is needed for the reaction.