Answer:
283.33 g of O2.
Step-by-step explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
2Mg + O2 —> 2MgO
Next, we shall determine the masses of Mg and O2 that reacted together from the balanced equation. This can be obtained as follow:
Molar mass of Mg = 24 g/mol
Mass of Mg from the balanced equation = 2 × 24 = 48 g
Molar mass of O2 = 16 × 2 = 32 g/mol
Mass of O2 from the balanced equation = 1 × 32 = 32 g
From the balanced equation above,
48 g of Mg reacted with 32 g of O2.
Finally, we shall determine the mass of O2 needed to react with 425 g of Mg as follow:
From the balanced equation above,
48 g of Mg reacted with 32 g of O2.
Therefore, 425 g of Mg will react with = (425 × 32)/48 = 283.33 g of O2.
Therefore, 283.33 g of O2 is needed for the reaction.