Answer:
![\angle P\approx67.38\textdegree](https://img.qammunity.org/2021/formulas/mathematics/high-school/c1525c99adignj5c82ncm4tgnn652x51jl.png)
Explanation:
We want to find the measure of ∠P.
To do so, we can use one of the three trigonometric functions.
Since we know the lengths of all of the sides, it doesn't matter which one we use: we will get the same result.
Let's use the sine ratio. Recall that sine is the ratio of the opposite side to the hypotenuse. That is:
![\displaystyle \sin(x)=\frac{\text{opposite}}{\text{hypotenuse}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/3fx6t1abboqct3p4g28v3uohx1e8h0q5cn.png)
Substitute ∠P for x. So:
![\displaystyle \sin(\angle P)=\frac{\text{opposite}}{\text{hypotenuse}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/bk96efc5hajdebk17iitib1amseji0tgus.png)
The opposite side to ∠P is 12. The hypotenuse is 13. Hence:
![\displaystyle \sin(\angle P)=(12)/(13)](https://img.qammunity.org/2021/formulas/mathematics/high-school/avne5ql6xq5ggep9xu9rbxp5b7jb6qrhca.png)
We can take the inverse sine of both sides:
![\displaystyle \angle P=\sin^(-1)\left((12)/(13)\right)](https://img.qammunity.org/2021/formulas/mathematics/high-school/l0g5vnnwq1jcnqp9bn6owroycgwg2vah9a.png)
Use a calculator. Make sure you're in degrees mode!
So, the measure of our angle is:
![\angle P\approx67.38\textdegree](https://img.qammunity.org/2021/formulas/mathematics/high-school/c1525c99adignj5c82ncm4tgnn652x51jl.png)
And we're done!