Question

A cat walks at a leisurely pace of 2 m/s. It spots a mouse and starts to sprint, chasing the mouse down the street. It takes the cat 3 s to reach a top speed of 20 m/s. Calculate the cat's rate of acceleration during this time.

Answer 1

`a=6\ m/s^2`

Step-by-step explanation:

Initial speed of a cat, u = 2m/s

It takes the cat 3 s to reach a top speed of 20 m/s.

We need to find the cat's rate of acceleration during this time. Acceleration is equal to the rate of change of velocity. So,

`a=(v-u)/(t)\\\\a=(20-2)/(3)\\\\a=6\ m/s^2`

So, the acceleration of the cat is
`6\ m/s^2`.