Complete question is;
A common way to describe the bonding energy curve for secondary bonding is the "6-12" potential. which states the bonding energy, E = - A/r^(6) + B/r^(12).
Write the expression that best represents the equilibrium bond length.
Answer:
Equilibrium bond length is;
r = (2B/A)^(1/6)
Step-by-step explanation:
We are given bonding energy as;
E = - A/r^(6) + B/r^(12)
Now let's find the derivative of this bonding energy with respect to r and equate to zero to find the bonding length(r).
Thus;
dE/dr = 6A/r^(7) - 12B/r^(13)
Equating to zero gives;
6A/r^(7) - 12B/r^(13) = 0
6A/r^(7) = 12B/r^(13)
Divide both sides by 6 to give;
A/r^(7) = 2B/r^(13)
2B/A = (r^(13))/(r^(7))
2B/A = r^(13 - 7)
2B/A = r^(6)
Thus, r = (2B/A)^(1/6)