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A rectangle has a perimeter of 48 inches. If twice the length decreased by three is equal to three times the width, the find the length and the width

User Schmalls
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2 Answers

1 vote
pretty sure the width would be 31
User Paul Geisler
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3 votes

Answer:

Length= 15, width= 9

Explanation:

perimeter of a rectangle P= 2(L+W)

L= length

W= width

48=2(L+W)---------------(1)

twice the length= 2×L= 3L

decreased by three= 2L-3

three times the width= 3×W= 3W

twice the length decreased by three is equal to three times the width

2L-3= 3W-------------------(2)

solving equation one and two simultaneously

from equation (2)

3W= 2L-3

W=2L/3-3/3

W= 2L/3 - 1----------(3)

substitute equation (3) into equation (1)

48=2(L+2L/3-1)

48=2L+4L/3-2

48×3=6L+4L-6

144=10L-6

10L=144+6

10L=150

dividing bothsides by 10

L= 15

substitute L= 15 into equation (2)

2L-3=3W

2(15)-3=3W

30-3 = 3W

27= 3W

3W= 27

dividing bothsides sides 3

3W=27/3

W=9

therefore, Length= 15, width= 9

User Palak Bansal
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3.2k points