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What is the equation of a line that has a slope of –3 and contains the point, (6, –5)? Express the equation in slope-intercept form, y = mx + b.

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Answer:

-5 = -3(5) + 10

Explanation:

y = mx + b

They have given you the x and y values and the slope, m

y = -3x + b

sub the ordered pair

-5 = -3(5) + b

-5 = -15 + b

add 15

10 = b

-5 = -3(5) + 10

User Dhruv Gohil
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