Question

A simple pendulum has length of 820mm. Calculate the frequency (g = 9.8 ms -2)
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Answer 1

`\huge\boxed{\sf f=0.55 \ Hz}`

Step-by-step explanation:

Given Data:

Length = l = 820 mm = 0.82 m

Acceleration due to gravity = g = 9.8 ms⁻²

Required:

Frequency = f = ?

Formula:

`\displaystyle f =(1)/(2 \pi) \sqrt{(g)/(l) }`

Solution:

`\displaystyle f =(1)/(2 \pi) \sqrt{(g)/(l) } \\\\Put\ the\ givens\\\\f=(1)/(2 \pi) \sqrt{(9.8)/(0.82) }\\\\ f = 0.159 * √(11.95) \\\\f=0.159 * 3.457\\\\f=0.55 \ Hz\\\\\rule[225]{225}{2}`