Question

Terry bought a gold necklace at a pawnshop and was wondering if it was “real” gold. She decided to perform a density test. She placed the necklace in a graduated cylinder of water that had 47.00 mL of water and the water rose to 48.35 mL. She then weighed the necklace and found it to have a mass of 22.89 g. What is the density of Terry’s necklace?

Answer 1

A

Step-by-step explanation:

The new mine means the supply is high and the price is low, so she can afford the necklace

Answer 2

d = 16.96 g/mL

Step-by-step explanation:

Given that,

Initial water level in graduated cylinder is 47 mL and final water level is 48.35 mL.

The weight of the neclace is 22.89 g.\

We need to find the volume of the necklace. We know that, density equals mass per unit volume. So,

`d=(m)/(V_f-V_i)\\\\d=(22.89\ g)/((48.35-47)\ mL)\\\\d=16.96\ g/mL`'

Hence, the density of Terry’s necklace is 16.96 g/mL.