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The length of a rectangle is eight more than twice its width. The perimeter is 88 feet. Find the dimensions of the rectangle.

A w = 10 ft, l = 18 ft

B w = 16 ft, l = 28 ft

C w = 18ft, l = 24 ft

D w = 12 ft, l = 32 ft

User Yoniyes
by
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1 Answer

3 votes

Answer:

D w = 12ft, l = 32ft

Step-by-step explanation:

Make an equation for your length based on the given information.

l = 2w + 8

Make an equation using what you know about the perimeter

p =2l + 2w, p = 88

88 = 2l +2w

Substitute in your previous equation for l.

88 = 2(2w + 8) + 2w

Distribute and simplify.

88 = 4w + 16 + 2w

88 = 6w + 16

72 = 6w

w = 12

Now you can solve for l using the first equation.

l = 2(12) + 8

l = 32

Your answer is w = 12fr, l = 32ft. You can check your work by plugging the values back into the perimeter equation.

User Mmalone
by
4.5k points
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