Question

The solutions to (x + 4) ^2- 2 = 7 are​

Answer 1

x = -1, -7

Explanation:

`(x+4)^2` -2 = 7

`(x+4)^2` -9 = 0 (Taking 7 to the other side)

`(x+4)^2` -
`3^2` = 0

Now use the difference of two squares rule

[((x+4)+3).((x+4)-3)] = 0

[(x+7).(x+1)] = 0

Now solve for x

x = -1, -7