Answer:
v = 17.14 m/s
Step-by-step explanation:
Given that,
Mass of eagle is 3.75 kg
We need to find the speed of Eagle after it has fallen freely from the rest through a distance of 15m. We can use third equation of motion :
![v^2-u^2=2as](https://img.qammunity.org/2021/formulas/physics/high-school/62imstr5dn6q95b14ng9iu55jgj34qnto2.png)
u = 0 (at rest) a= g
![v^2=2gs\\\\v=√(2gs) \\\\v=√(2* 9.8* 15) \\\\v=17.14\ m/s](https://img.qammunity.org/2021/formulas/physics/high-school/n4n6la1lwb4riuovd190h5und5mjt12pa6.png)
so, the speed of the eagle is 17.14 m/s.