Question

PLEASE HELP ASAP

What is an equation of the line that passes through the points (3, 2) and (6, -3)?

Answer 1

(y+2)=2(x−3)

Or

(y−4)=2(x-6)

Or

y=2x−8

Explanation:

Answer 2

`y= -(5)/(3) x+7`

In order to find equation:

Find slope:

`\sf slope: (y_2- y_1)/(x_2 -x_1) = (rise)/(run)` where (x1, y1), (x2, y2)

`\hookrightarrow \sf slope: (-3-2)/(6-3)`

`\hookrightarrow \sf slope:- (5)/(3)`

Find Equation:

`\boxed{\sf y - y_1 = m(x_1 -x)}` "m" is slope

`\sf \rightarrow y-2 = -(5)/(3) (x-3)`

`\sf \rightarrow y-2 = -(5)/(3) x+5`

`\sf \rightarrow y= -(5)/(3) x+5+2`

`\sf \rightarrow y= -(5)/(3) x+7`