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The circle below is centred at O.

AB is a tangent to this circle.
Work out the size of angle y.
Justify your answer.
O
42°
y
A
B
Not drawn accurately

The circle below is centred at O. AB is a tangent to this circle. Work out the size-example-1
User Ducktyped
by
4.6k points

2 Answers

10 votes

Answer:

y = 48°

Explanation:

angle A = 90°

interior angles of a triangle = 180°

therefore

y = 180 - 42 - 90

y = 48°

User Arismendy
by
4.3k points
7 votes


\huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }

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❒ Given ❒

  • ➣ Mid point of a circle
  • ➣ Tangent AB
  • ➣ Angle "o" of 42⁰
  • ➣ Angle "A" of 90⁰ (cuz it is the perpendicular of traingle given in circle)

﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌

❒ Note ❒

  • ➣here tangent AB with point O (mid point of circle) forming a traingle
  • ➣we have to find "y" in the given figure (angle B)

﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌

❒ Concept used ❒

  • ➣The sum of interior angles of traingle is of 180⁰
  • ➣to find the missing angle ( y ) we will use this theorem
  • ➣this Concept is also know as Sum theorem

﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌﹌

❒ Assumption ❒

  • ➣angle B = y

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❒ Let's solve ❒


\large \pmb{➪ \: } \rm \pink{ \angle \: OAB+\angle \:ABO+\angle \:BOA = 180 \degree}

  • ➣let's substitute value now .....


\pmb{➪ \: 90 + y +42 = 180 } \\ \pmb{➪ \:132 + y = 180 \: \: \: \: \: \: \: \: }\\ \pmb{➪ \:y = 180 - 132 \: \: \: \: \: \: \: \: }\\ \pmb{➪ \:y = 48 \degree \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }

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Hence the size of angle is


\large \boxed{✥\underline{ \boxed{ \sf{y = 48 \degree \: \pmb{\green{✓}} }}}✥}

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Hope it helps !

User Jerimiah
by
4.3k points