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Solve 5(2y+1)=4y+10. this is for algebra 1

User Doingweb
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5(2y+1)=4y+10(multiply 5 to 2y and 1)
10y+5=4y+10(subtract 5 from 5 and 10)
10y=4y+5(subtract 4y from 4y and 10y)
6y=5(divide 6 by 6y and 5)
y=0.83

User Unjuken
by
8.9k points
2 votes

Answer:


y=5/6\approx0.83

Explanation:

So we have the equation:


5(2y+1)=4y+10

First, let's distribute the left side of our equation:


5(2y)+5(1)=4y+10

Multiply:


10y+5=4y+10

Now, let's isolate the y-variable. Subtract 4y from both sides:


(10y+5)-4y=(4y+10)-4y

The right side cancels. Subtract on the left. So:


6y+5=10

Now, subtract 5 from both sides:


(6y+5)-5=(10)-5

The left side cancels. Subtract on the right:


6y=5

Now, divide both sides by 6. So:


(6y)/(6)=(5)/(6)

The left will cancel. Therefore:


y=5/6\approx0.83

And we're done!

User Lakma Chehani
by
8.2k points

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