Question

Solve 5(2y+1)=4y+10. this is for algebra 1

Answer 1

5(2y+1)=4y+10(multiply 5 to 2y and 1)
10y+5=4y+10(subtract 5 from 5 and 10)
10y=4y+5(subtract 4y from 4y and 10y)
6y=5(divide 6 by 6y and 5)
y=0.83

Answer 2

`y=5/6\approx0.83`

Explanation:

So we have the equation:

`5(2y+1)=4y+10`

First, let's distribute the left side of our equation:

`5(2y)+5(1)=4y+10`

Multiply:

`10y+5=4y+10`

Now, let's isolate the y-variable. Subtract 4y from both sides:

`(10y+5)-4y=(4y+10)-4y`

The right side cancels. Subtract on the left. So:

`6y+5=10`

Now, subtract 5 from both sides:

`(6y+5)-5=(10)-5`

The left side cancels. Subtract on the right:

`6y=5`

Now, divide both sides by 6. So:

`(6y)/(6)=(5)/(6)`

The left will cancel. Therefore:

`y=5/6\approx0.83`

And we're done!