Question

A balloon contains 7.2 L of

He. The pressure is reduced
to 2.00 atm and the balloon
expands to occupy a volume
of 25.1 L. What was the initial
pressure exerted on the
balloon?

Given:
Unknown:
Formula:
Solution:
Final Answer:​

Answer 1

Apply Boyles law

• P1V1=P2V2
• 7.2(2)=25.1P2
• 14.4=25.1P_2
• P_2=0.57atm

Remember

If Volume is four times increased pressure is 4 times decreased