Please help I need to know now :(

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asked Apr 19, 2021 167k views

5 votes

Please help I need to know now :(

Mathematics
high-school

Bert Smith asked

by Bert Smith

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2 Answers

3 votes

I think it’s y^2.
...

Wades answered Apr 22, 2021

by Wades

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5 votes

Answer:

$(6x*x^(3))/(y^(2))\\\\$

Explanation:

$a^(-m)=(1)/(a^(m))\\\\(1)/(a^(-m))=a^(m)\\\\a^(m)*a^(n)=a^(m+n)\\\\\\(6xy^(-2))/(x^(-3))=(6*x*x^(3))/(y^(2))\\\\=(6x^((1+3)))/(y^(2))\\\\=(6x^(4))/(y^(2))$

Loremar Marabillas answered Apr 23, 2021

by Loremar Marabillas

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