Answer:
d = 180 m.
Step-by-step explanation:
We can find the distance where the car and the truck will be side-by-side as follows:
For the car we have:
Where:
is the final position
is the initial position = 0
is the initial speed = 0
: is the acceleration = 2.5 m/s²
t: is the time
(1)
For the truck we have:
![X_(f) = X_(0) + V_(0)t + (1)/(2)at^(2)](https://img.qammunity.org/2021/formulas/physics/college/tjljlottc2qqno9s4jv7yboic8kccyi8iy.png)
![X_(f) = 0 + V_(0)t + (1)/(2)0*t^(2)](https://img.qammunity.org/2021/formulas/physics/college/o69ecdm80p1vqa9ck71vw2td581iqlyyve.png)
(2)
By equating equation (1) and (2) we have:
![t = (2V_(0))/(a_(c)) = (2*15 m/s)/(2.5 m/s^(2)) = 12 s](https://img.qammunity.org/2021/formulas/physics/college/z5rmtdyfxmsacipycu5tx81gibs3orcec7.png)
Since the car and the truck will be side-by-side at 12 seconds, we can calculate now the distance:
Therefore, the distance at which the car and the truck will be side-by-side is 180 m.
I hope it helps you!