Question

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Answer 1

t = 300

Explanation:

`\huge P = 10(2)^{ (t)/(60) } \\ \\ \huge 320 = 10(2)^{ (t)/(60) }\\(plug \: P= 320) \\ \\ \huge (320)/(10) = (2)^{ (t)/(60) } \\ \\ \huge 32 = (2)^{ (t)/(60) } \\ \\\huge {2}^(5) = (2)^{ (t)/(60) } \\ \\\huge 5 = (t)/(60) \\(bases\: are \:same, \:so \:exponents \: would \:be\: \\equal) \\ \huge 5 * 60 = t \\ \\300 = t \\ \\\huge\purple {\boxed {t = 300}}`

Answer 2

• 300

Explanation:

Given, the function:

• P = 10(2)^(t/60)

To find

• t if P= 320

Solution

Substituting P with its value of 320 in the given equation:

• 320 = 10(2)^(t/60)
• 32= (2)^(t/60)
• 2^5 = (2)^(t/60)
• 5 = t/60
• t = 60*5
• t = 300