64.2k views
13 votes
Find three consecutive integers such that their sum is 40 more that tiwce the middle integer.

User Prentice
by
8.4k points

1 Answer

4 votes

Answer:

39, 40, 41

Explanation:

Let x represent the middle integer. The sum of the three integers will be ...

(x -1) +x +(x +1) = 3x

This is 40 more than 2 times the middle integer, so we have ...

3x = 40 +2x

x = 40 . . . . . . . subtract 2x

The three integers are 39, 40, 41.

_____

Additional comment

It often works well to solve consecutive integer problems by letting a variable represent the middle value, or the average of the integers.

User Glaux
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories