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Find three consecutive integers such that their sum is 40 more that tiwce the middle integer.

User Prentice
by
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1 Answer

4 votes

Answer:

39, 40, 41

Explanation:

Let x represent the middle integer. The sum of the three integers will be ...

(x -1) +x +(x +1) = 3x

This is 40 more than 2 times the middle integer, so we have ...

3x = 40 +2x

x = 40 . . . . . . . subtract 2x

The three integers are 39, 40, 41.

_____

Additional comment

It often works well to solve consecutive integer problems by letting a variable represent the middle value, or the average of the integers.

User Glaux
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5.7k points