Question

Hypothetically, if you weighed out 0.8036 g of NaOH, what would the exact NaOH solution concentration be

Answer 1

Complete question

The complete question is shown on the first uploaded image

Answer:

The value is
`C = 0.02009 \ M`

Step-by-step explanation:

From the question we are told that

The mass of NaOH is
`m= 0.8036 g`

In the question DI (stands for de-ionized water )

So the number of moles of NaOH present in the given mass is

`n = (m)/(Z)`

Here Z is the molar mass of NaOH with value
`Z = 40 \ g/ mol`

So

`n = (0.8036)/(40)`

`n =0.02009 \ mols`

Given that the volume of the flask is V = 1 L then we can evaluated the concentration as

`C = (n)/(V)`

=>
`C  =  (0.02009)/(1)`

=>
`C  =  0.02009 \ M`