Answer:
![x\leq 3](https://img.qammunity.org/2021/formulas/mathematics/high-school/1o9rl3y7l7jek7dfsjljpb8u5ukvh5f9us.png)
Explanation:
So we have the inequality:
![2(4+2x)\geq 5x+5](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vlkiij915w92yhzfh1izcc12n3cwvlofty.png)
First, let's distribute the left side:
![2(4)+2(2x)\geq 5x+5](https://img.qammunity.org/2021/formulas/mathematics/high-school/1swdrw7svl9xfc4zs5duh4ukfs6rz0z3qy.png)
Multiply:
![8+4x\geq5x+5](https://img.qammunity.org/2021/formulas/mathematics/high-school/7nejsh3wq2ecpd6vuqg0ok25t2fa8nl5zp.png)
Now, let's isolate the x-variable. Subtract 8 from both sides:
![(8+4x)-8\geq (5x+5)-8](https://img.qammunity.org/2021/formulas/mathematics/high-school/rgco3pqcn3dq7h2avihyfzzbnqw2q0zn1y.png)
The left side cancels. Subtract on the right:
![4x\geq 5x-3](https://img.qammunity.org/2021/formulas/mathematics/high-school/ce98xmagsxv7zz6bf6kjflre76fc2vb67y.png)
Now, let's subtract 5x from both sides:
![(4x)-5x\geq (5x-3)-5x](https://img.qammunity.org/2021/formulas/mathematics/high-school/n2kovqyde8rqoxlo5hfu0fgi9f10rx2o4f.png)
The right side cancels. Subtract on the left:
![-x\geq -3](https://img.qammunity.org/2021/formulas/mathematics/high-school/j4hd884uluqbu0g2vu87jawhw2ewz4130e.png)
Now, let's multiply both sides by -1.
Since we're multiplying by a negative, we flip the sign. So:
![-1(-x)\leq (-1)(-3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/j707ldqzl9tpnv9d2bgabkru9gtvk8p216.png)
Multiply:
![x\leq 3](https://img.qammunity.org/2021/formulas/mathematics/high-school/1o9rl3y7l7jek7dfsjljpb8u5ukvh5f9us.png)
So, our solution is all numbers less than or equal to 3.
And we're done!