Answer:
![r_(Br_2)=2.1x10^(-4)M/s](https://img.qammunity.org/2021/formulas/chemistry/college/uvg1h7ja3opsx24co0j3504c91mdlo5tc6.png)
Step-by-step explanation:
Hello,
In this case, for the reaction:
![5Br^-(aq)+BrO_3^-(aq)+6H^+(aq)\rightarrow 3Br_2(aq)+3H_2O(l)](https://img.qammunity.org/2021/formulas/chemistry/college/8nutpbezrns36rbzgr19tdvxie11h31cg3.png)
Thus, via the rate proportions between Br⁻ and Br₂ for which the stoichiometric coefficients are 5 and 3 respectively, we can write:
![(r_(Br^-))/(-5) =(r_(Br_2))/(3)](https://img.qammunity.org/2021/formulas/chemistry/college/xiai1nwreypo5rh91b31jebjq103nqhdzt.png)
Hence, the rate of appearance of Br₂ turns out:
![r_(Br_2)=(3r_(Br^-))/(-5)=(3*-3.5x10^(-4)M/s)/(-5)\\ \\r_(Br_2)=2.1x10^(-4)M/s](https://img.qammunity.org/2021/formulas/chemistry/college/sumv7spp8l9msj4pl555m462tw0mq282mg.png)
Take into account that the rate of disappearance is negative for reactants.
Best regards.