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In the reaction 5 space B r to the power of minus space (a q )space plus space B r O subscript 3 to the power of minus space (a q )space plus space 6 space H to the power of plus space (a q )space rightwards arrow space 3 space B r subscript 2 space (a q )space plus space 3 space H subscript 2 O space (l )the rate of disappearance of Br- at some moment in time was determined to be 3.5 x 10-4 M/s. What is the rate of appearance of Br2 at that same moment

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Answer:


r_(Br_2)=2.1x10^(-4)M/s

Step-by-step explanation:

Hello,

In this case, for the reaction:


5Br^-(aq)+BrO_3^-(aq)+6H^+(aq)\rightarrow 3Br_2(aq)+3H_2O(l)

Thus, via the rate proportions between Br⁻ and Br₂ for which the stoichiometric coefficients are 5 and 3 respectively, we can write:


(r_(Br^-))/(-5) =(r_(Br_2))/(3)

Hence, the rate of appearance of Br₂ turns out:


r_(Br_2)=(3r_(Br^-))/(-5)=(3*-3.5x10^(-4)M/s)/(-5)\\ \\r_(Br_2)=2.1x10^(-4)M/s

Take into account that the rate of disappearance is negative for reactants.

Best regards.

User Balconsky
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