Question

A truck is stopped at a stop sign. After realizing the driver should go straight, he accelerates the truck at a constant rate of 3.6 m/s2 for 9.4 seconds. What is the car’s final velocity? (Numbers only. Round to 1 decimal)

Answer 1

v = 33.8 m/s

Explanation:

Given that,

The initial velocity of the truck, u = 0

Acceleration of the truck, a = 3.6 m/s²

Time, t = 9.4 s

We need to find the car's final velocity. Let v is the final velocity.

Using equation of kinematics as follows :

v = u +at

Since, u = 0

`a=3.6* 9.4\\\\v=33.8\ m/s`

Hence, the final velocity of the car is 33.8 m/s.