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5 votes
Find the distance points p (3,6) and q (7,3) to the nearest tenth?

2 Answers

3 votes

Answer:

5 points

Explanation:

I gave up with the equation writing thing on here so hope you can read my writing. It's already rough and now I'm in a brace but I hope his helps

Find the distance points p (3,6) and q (7,3) to the nearest tenth?-example-1
User Naryl
by
8.7k points
4 votes

Answer: 5

=========================================================

One method is to plot the points P(3,6) and Q(7,3) on the same xy grid. Plot a third point R at (3,3). See the diagram below.

A right triangle forms in which we can find the legs PR = 3 and RQ = 4. The hypotenuse is found through the pythagorean theorem.

a^2+b^2=c^2

3^2+4^2 = c^2

9+16 = c^2

c^2 = 25

c = sqrt(25)

c = 5

This is the length of PQ

-----------------------------------

Or you can use the distance formula which is effectively using the pythagorean theorem just in a slightly different format (though it may not be obvious).


d = \text{Distance from P to Q}\\\\d = √((x_1-x_2)^2+(y_1-y_2)^2)\\\\d = √((3-7)^2+(6-3)^2)\\\\d = √((-4)^2+(3)^2)\\\\d = √(16+9)\\\\d = √(25)\\\\d = 5\\\\

Find the distance points p (3,6) and q (7,3) to the nearest tenth?-example-1
User Emel
by
8.5k points

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