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A man on a road trip drives a car at different constant speeds over several legs of the trip. He drives for 55.0 min at 60.0 km/h, 18.0 min at 80.0 km/h, and 60.0 min at 60.0 km/h and spends

25.0 min eating lunch and buying gas.

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Complete Question

A man on a road trip drives a car at different constant speeds over several legs of the trip. He drives for 55.0 min at 60.0 km/h, 18.0 min at 80.0 km/h, and 60.0 min at 60.0 km/h and spends

25.0 min eating lunch and buying gas

What is the total distance traveled over the entire trip (in km)

Answer:

The value is
D = 139.02 \ km

Step-by-step explanation:

From the question we are told that

For
t_1 = 55 min = (55)/(60) = 0.917 \ h the speed is
v_1 = 60 \ km/h

For
t_2 = 18 min = (18)/(60) = 0.3 \ h the speed is
v_2 = 80 \ km/h

For
t_3 = 60 min = (60)/(60) = 1 \ h the speed is
v_3 = 60\ km/h

The time taken to have lunch is
t _l = 25 \ min = (25)/(60) = 0.42 \ h

Generally the total distance traveled over the entire trip (in km) is mathematically represented as


D = t_1 * v_1 + t_2 * v_2 + t_3 * v_3

=>
D = 0.917  *  60 +  0.3 * 80 +  1  * 60

=>
D = 55.02  + 24 +   60

=>
D = 139.02 \ km

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