Question

Find the midpoint of the line segment with these endpoints. (2, -3) and (4, -1)

Answer 1

`\huge{ \fbox{ \sf{( \: 3 \: , \: - 2)}}}`

Explanation:

`\star{ \: \sf{ \: Let \: the \: points \: be \: A \: and \: B}}`

`\star{ \sf{ \: Let \: A(2, -3) \: be \: (x1 \:, y1) \: and \: B(4, -1) \: be \: (x2 ,\: y2)}}`

`\underline{ \sf{Finding \: the \: midpoint}} :`

`\boxed{ \sf{Midpoint = ( (x1 + x2)/(2) \: , \: (y1 + y2)/(2)) }}`

`\mapsto{ \sf{Midpoint = ( (2 + 4)/(2) \: , \: ( - 3 + ( - 1))/(2) }})`

`\underline{ \text{Remember!}} : \sf{( + ) * ( - ) = ( - )}`

`\mapsto{ \sf{Midpoint = ( (2 + 4)/(2) \: , \: ( - 3 - 1)/(2) }})`

`\underline{ \text{Remember!}} : \sf{The \: negative \: integers \: are \: always \: added \: but \: posses \: the \: negative( - ) \: sign.}`

`\mapsto{ \sf{Midpoint = ( (6)/(2) \: , \: ( - 4)/(2) }})`

`\underline{ \text{Remember!}} : \sf{Dividing \: a \: negative \: integer \: by \: a \: positive \: integer\: gives \: a \: negative \: integer.}`

`\mapsto{ \boxed{ \sf{Midpoint = ( \: 3 \: , \: - 2})}}`

Hope I helped!

Best regards! :D

~TheAnimeGirl

Answer 2

The midpoint of the line segment is (3,-2)