Question

asked Oct 22, 2021 205k views

2 Answers

Ossama · Answer 1 · 2021-10-23T13:54:34+0000

Answer:

$\huge{ \boxed{ \sf{ - 6 {x}^(2) + 6x + 3}}}$

Explanation:

$\underline{ \sf{ \:First ,\: Adding : 2x - {x}^(2) + 5 \: and \: - 4x - 3 + 7 {x}^(2) }}$

$\sf{2x - {x}^(2) + 5 + ( - 4x - 3 + 7 {x}^(2) })$

$\text{Step \: 1} :$ In addition , sign of each term in the expression remains unchanged. Just remove the unnecessary parentheses.

$\mapsto{ \sf{ - 2x - {x}^(2) + 5 - 4x - 3 + 7 {x}^(2) }}$

$\text{Step \: 2} :$ Collect like terms and simplify

Like terms are those which have the same base.

$\mapsto{ \sf{ - {x}^(2) + 7 {x}^(2) - 2x - 4x + 5 - 3}}$

$\underline{ \sf{Remember!}} :$

The negative and positive integers are always subtracted but posses the sign of the bigger integer.
The negative integers are always added but posses the negative ( - ) sign.
The positive integers are always added and posses the positive ( + ) sign.

$\mapsto{ \sf{6 {x}^(2) - 6x + 2}}$

$\underline{ \sf{Now ,\: Subtracting \: 6 {x}^(2) - 6x + 2 \: from \: 5}}$

$\sf{5 - (6 {x}^(2) - 6x + 2)}$

$\text{Step \: 1} :$ While subtracting, sign of each term of the second expression changes.

$\mapsto{ \sf{5 - 6 {x}^(2) + 6x - 2}}$

$\mapsto{ \sf{ 5 - 2 - 6 {x}^(2) + 6x}}$

$\text{step \: 2} : \sf{Subtract \: 2 \: from \: 5}$

$\mapsto{ \sf{ 3 - 6 {x}^(2) + 6x}}$

Now, Rewrite the expression in standard form. That means , You have to arrange the terms having greatest power to lowest.

$\mapsto{ \sf{ - 6 {x}^(2) + 6x + 3}}$

Hope I helped!

Best regards! :D

~
$\sf{TheAnimeGirl}$

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