Question

Calculate the mass of NaOH required to make 300 CM3 of 0.2M solution​

Answer 1

Mass of NaOH = 2.4 grams

Step-by-step explanation:

`M\:=\:(n)/(v)`

where,

`n=moles\:of\:solute`

`v=liters\:of\:solution`

Remember:
`\quad 1000\:cm^3=1\:L`

`\Rightarrow \quad 300\:cm^3=0.3\:L`

`n=(m)/(40\:g/mol)`

Putting the values, we have:

`0.2=(m)/(40\:g/mol)* (1)/(0.3)`

`\Rightarrow m=2.4\:g`

Best Regards!