Calculate the mass of NaOH required to make 300 CM3 of 0.2M solution

asked Oct 2, 2021 180k views

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Answer:

Mass of NaOH = 2.4 grams

Step-by-step explanation:

$M\:=\:(n)/(v)$

where,

$n=moles\:of\:solute$

$v=liters\:of\:solution$

Remember:
$\quad 1000\:cm^3=1\:L$

$\Rightarrow \quad 300\:cm^3=0.3\:L$

$n=(m)/(40\:g/mol)$

Putting the values, we have:

$0.2=(m)/(40\:g/mol)* (1)/(0.3)$

$\Rightarrow m=2.4\:g$

Best Regards!

Mokmeuh answered Oct 6, 2021

6.7k points

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