Question

The area of a rectangle is 48 cm². If its width is 6 cm, what is its length?

Answer 1

AREA

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`\large \sf \underline{Question:}`

• The area of a rectangle is 48 cm². If its wdth is 6 cm, what is its length

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`\large \sf \underline{Answer:}`

`\qquad \qquad \qquad \huge \bold{8cm}`

To solve for the area of rectangle, you use this formula A = length × width. But we're doing it reversal, we will divide the width to the area

• 
  `\large\tt{A \: = \: l \: * \: w}`

• 
  `\large\tt{48cm^(2) \: = \: l \: * \: 6cm}`

• 
  `\large\tt{48cm^(2) \: / \: 6cm \: = \: l}`

• 
  `\large\tt{48cm^(2) \: / \: 6cm \: = \: \pmb{8cm}}`

Therefore, The length is 8cm.

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Answer 2

Hey ! there

Answer:

• Length of rectangle is 8 cm .

Explanation:

In this question we are provided with a rectangle having area 48 cm² and width 6 cm . We are asked to find the length of rectangle .

We know that ,

`\qquad \qquad\underline{\boxed{\frak{Area_((Rectangle)) = l * w}}}`

Where ,

• l refers to Length

• w refers to Width

SOLUTION : -

We are finding value of length by substituting value of width as 6 cm and area as 48 cm² in the formula . So ,

`\quad\longmapsto \qquad \:48 = 6 * l`

or ,

`\quad\longmapsto \qquad \:48 = 6l`

Dividing with 6 on both sides :

`\quad\longmapsto \qquad \: \cancel{(48)/(6)} = \frac{ \cancel{6}l}{ \cancel{6}}`

We get ,

`\quad\longmapsto \qquad \: \orange{\underline{\boxed{ \frak{l = 8 \: cm}}}} \quad \bigstar`

• Henceforth , Length of rectangle having area 48 cm² and width 6 cm is ❝ 8 cm ❞

Verifying : -

We are verifying our answer by substituting value of length and width in formula and equating it with given area . So ,

• 
  `8 * 6 = 48`

• 
  `48 = 48`

• 
  `\rm{L.H.S = R.H.S}`

• 
  `\rm{Hence , \: Verified .}`

Therefore , our answer is correct .

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