If h(x)=x2-5+7. h(2) x2 ​

Question

If h(x)=x2-5+7.
h(2)

`x2`
​

Answer 1

The way to solve this is by re-writing the equation except with 2 as x.
h(x)= x^2-5+7
h(2)= 2^2-5+7
h(2)=4-5+7
h(2)=-1+7
h(2)= 6