96.6k views
5 votes
If h(x)=x2-5+7.
h(2)

x2


1 Answer

5 votes
The way to solve this is by re-writing the equation except with 2 as x.
h(x)= x^2-5+7
h(2)= 2^2-5+7
h(2)=4-5+7
h(2)=-1+7
h(2)= 6
User Elliott
by
4.6k points