Question

WHAT THE HECC IS THIS

Answer 1

h(x)

Explanation:

to solve for an inverse, you swap the x and the y and then solve for y

f(x) = 4x^3-8

y = 4x^3 - 8

x = 4y^3 - 8 swap the x and y

now solve for y:

x + 8 = 4y^3

(x + 8)/4 = y^3

1/4x + 8/4 = y^3

1/4x + 2 = y^3

y =
`\sqrt[3]{1/4x + 2}`