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What would happen if N2 were added to N2(g) + O2(g) = 2NO(9) at

equilibrium?

O A. Keq would decrease

O B. More No would form.

O C. More O2 and No would form.

O D. More N2 and Oz would form.

User Ptica
by
5.3k points

2 Answers

4 votes

Final answer:

If N2 were added to the equation N2(g) + O2(g) = 2NO(g) at equilibrium, the system would shift to the right to form more NO.

Step-by-step explanation:

If N2 were added to the equation N2(g) + O2(g) = 2NO(g) at equilibrium, the system would shift to the right to form more NO. This is because Le Chatelier's principle states that if a stress is applied to a system at equilibrium, the system will try to counteract that stress to reach a new equilibrium. In this case, adding N2, which is a reactant, would increase the concentration of reactants and shift the equilibrium to the right to form more product, which is NO.

User Koushik Roy
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5.2k points
5 votes

Balanced chemical equation is :


N_2(g)+O_2(g)-->2NO(g)

It is given that the equation is in equilibrium.

We need to find what will happen if we add more
N_2 is added .

By Le Chatelier's principle :

Changing the concentration of a chemical will shift the equilibrium to the side that would counter that change in concentration.

It means production of the side where content is added will decrease and concentration on other side will increase .

So , more NO would form .

Therefore, option B. is correct.

Hence, this is the required solution.

User Mounika
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4.8k points