Question

For what values of y:

is the value of the binomial 5y−1 greater than the value of the fraction 3y−1/4 ?

Answer 1

`y > (3)/(17)`

Explanation:

To solve this problem, simply set the binomial,
`5y - 1` as greater than
`(3y - 1)/(4)`, and solve for the value of y as you would solve an equation.

Thus:

`5y - 1 > (3y - 1)/(4)`

Multiply both sides by 4

`4(5y - 1) > (3y - 1)/(4)*4`

`4*5y - 4*1 > 3y - 1`

`20y - 4 > 3y - 1`

Subtract 3y from both sides

`20y - 4 - 3y > 3y - 1 - 3y`

`17y - 4 > -1`

Add 4 to both sides

`17y - 4 + 4 > -1 + 4`

`17y > 3`

Divide both sides by 17

`(17y)/(17) > (3)/(17)`

`y > (3)/(17)`

Therefore, the value of y that will make the binomial
`5y - 1` greater than
`(3y - 1)/(4)` is
`y > (3)/(17)`.