Question

A certain sample of a gas has a volume of 20 L at 0 oC and 1 atm. A plot of the experimental data of its volume against the Celsius temperature, θ, at constant P, gives a straight line of slope 0.0741 L(C)^-1. From these data alone (without making use of the perfect gas law), determine the absolute zero of temperature in degrees Celsius.

Answer 1

The absolute zero temperature T = - 269.91° C

Step-by-step explanation:

From the given information:

The plot of the volume of the experimental data against the celsius temperature can be expressed mathematically as:

V = mT + c

V = 0.0741 × T+c --- (1)

where;

m, which is the straight line of the slope = 0.0741

replacing the value of V to be = 20 L, T= 0.

Then:

20 = 0.0741 × 0 + c

20 = c

From equation (1), replacing the value of c with 20, we have:

V = 0.0741 × T+20

SO, to determine absolute zero temperature: we have the volume to be zero at absolute zero temperature, Thus:

0 = 0.0741 × T+20

0.0741 T + 20 = 0

0.0741 T = - 20

`\mathbf{T = (-20)/(0.0741)}`

T = - 269.91° C