Answer:
Your input: find the distance between P=(−3,11)
P
=
(
−
3
,
11
)
and Q=(−6,4)
Q
=
(
−
6
,
4
)
.
The distance between two points is d=(x2−x1)2+(y2−y1)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√
d
=
(
x
2
−
x
1
)
2
+
(
y
2
−
y
1
)
2
.
We have that x1=−3
x
1
=
−
3
, y1=11
y
1
=
11
, x2=−6
x
2
=
−
6
, y2=4
y
2
=
4
.
So, d=(−6−(−3))2+(4−(11))2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√=58‾‾‾√
d
=
(
−
6
−
(
−
3
)
)
2
+
(
4
−
(
11
)
)
2
=
58
.
Answer: d=58‾‾‾√≈7.61577310586391
d
=
58
≈
7.61577310586391
.
Explanation:
Hey! Got this off of someone else ages ago.. hope this helps tho