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5 votes
HELP PLS!! Find the distance between (-3, 11) and (-6, 4). Round to the nearest tenth.

1 Answer

5 votes

Answer:

Your input: find the distance between P=(−3,11)

P

=

(

3

,

11

)

and Q=(−6,4)

Q

=

(

6

,

4

)

.

The distance between two points is d=(x2−x1)2+(y2−y1)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√

d

=

(

x

2

x

1

)

2

+

(

y

2

y

1

)

2

.

We have that x1=−3

x

1

=

3

, y1=11

y

1

=

11

, x2=−6

x

2

=

6

, y2=4

y

2

=

4

.

So, d=(−6−(−3))2+(4−(11))2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√=58‾‾‾√

d

=

(

6

(

3

)

)

2

+

(

4

(

11

)

)

2

=

58

.

Answer: d=58‾‾‾√≈7.61577310586391

d

=

58

7.61577310586391

.

Explanation:

Hey! Got this off of someone else ages ago.. hope this helps tho

User Vahid Amiri
by
7.9k points

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