Question

The area of a blackboard is 1 1 third square yards. A poster’s area is 8 over 9 square yards. What is the unit rate of the blackboard's area to the poster's area? (plz dont take points)

Answer 1

`\qquad {:}\longrightarrow\tt 1\frac {1}{3}=(4)/(3)`

• Now answer

`\qquad {:}\longrightarrow\displaystyle\tt \frac {\frac {4}{3}}{\frac {8}{9}}`

• Simplify

`\qquad {:}\longrightarrow\tt \frac {4}{3}* \frac {9}{8}`

`\qquad {:}\longrightarrow\tt \frac {36}{24}`

`\qquad {:}\longrightarrow\tt \frac {3}{2}`

`\qquad {:}\longrightarrow\tt 1.5 \:per\:unit`

Answer 2

Explanation:

(1 ⅓ yd²) / (8/9 yd²)

(4/3 yd²) / (8/9 yd²)

(4/3) × (9/8)

3/2

1.5 / 1