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8 votes
What is the distance between B to A

Please add the method.
The angle is 61 (a bit blurry)

What is the distance between B to A Please add the method. The angle is 61 (a bit-example-1
User Trinition
by
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2 Answers

8 votes
  • OH=1980

Now

  • tan61=BH/OH
  • tan61=BH/1980
  • BH=1980tan61
  • BH=3572(Rounded)

AB

  • 8+3572
  • 3580
14 votes

Answer:

24.03 units (nearest hundredth)

Explanation:

The distance between B and A is: AB = AH + HB

We have been given AH, so we just need to find the measure of HB.

First, find the angle AOH using tan trig ratio:


\sf \tan(\theta)=(O)/(A)

where:


  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

Given:


  • \theta = ∠AOH
  • O = AH = 8
  • A = OH = 19.80


\implies \sf \tan(\angle AOH)=(8)/(19.8)


\implies \sf \angle AOH = 22.00069835^(\circ)

∠BOA = ∠BOH + ∠AOH

⇒ ∠BOH = ∠BOA - ∠AOH

⇒ ∠BOH = 61° - 22.00069835°

= 38.99930165°

Now we can find HB by again using the tan trig ratio:

Given:


  • \theta = ∠BOH = 38.99930165°
  • O = HB
  • A = OH = 19.80

Substituting given values:


\implies \sf \tan(38.99930165^(\circ))=(HB)/(19.80)


\implies \sf HB=19.80 \tan(38.99930165^(\circ))


\implies \sf HB=16.03332427

Therefore:

AB = AH + BH

⇒ AB = 8 + 16.03332427

= 24.03 units (nearest hundredth)

What is the distance between B to A Please add the method. The angle is 61 (a bit-example-1
User Dbn
by
8.9k points

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