Question

Find the missing side

Answer 1

Explanation:

We have,

• Perpendicular = 16
• Hypotenuse = 18
• Base = x

We know that,

`\large\boxed{\sf (Hypotenuse)^2=(Perpendicular)^2+(Base)^2}`

`\longmapsto \sf \: (18)^2=(16)^2+x^2`

`\longmapsto \sf \: (18)^2-(16)^2=x^2`

`\longmapsto \sf \: x^2=324-256`

`\longmapsto \sf \: x^2=68`

`\longmapsto \sf \: x = √(68)`

`\longmapsto \sf \: x ≈8.25`

Answer 2

`\huge\boxed{\sf x = 8.2}`

Explanation:

Since it is a right-angled triangle, we will apply Pythagoras Theorem.

Given are:

Base = 16

Perpendicular = x

Hypotenuse = 18

Pythagoras Theorem:

`\sf (Hypotenuse)^2=(Base)^2+(Perpendicular)^2`

(18)² = (16)² + (x)²

324 = 256 + x²

Subtract 256 to both sides

324 - 256 = x²

68 = x²

Take sqrt on both sides

8.2 = x

x = 8.2

`\rule[225]{225}{2}`