Question

The sum of five consecutive even integers is

110. What is the sum of the smallest three of
these five integers?

Answer 1

By assigning a variable to the smallest integer and setting up an equation, we find that the smallest of the five consecutive even integers is 18. The sum of the smallest three integers (18, 20, and 22) is 60.

Step-by-step explanation:

To solve the problem of finding the sum of the smallest three of five consecutive even integers whose total sum is 110, we can use algebra. Let's define the smallest integer as 'x'. The next four consecutive even integers would be 'x + 2', 'x + 4', 'x + 6', and 'x + 8'. The sum of these five even integers is:

x + (x + 2) + (x + 4) + (x + 6) + (x + 8) = 110

Simplifying:

5x + 20 = 110

Subtract 20 from both sides:

5x = 90

Now divide by 5:

x = 18

Therefore, the smallest integer is 18. The sum of the smallest three integers is:

18 + (18 + 2) + (18 + 4) = 18 + 20 + 22 = 60

Answer 2

The answer is 63

The integers are 20, 21, 22, 23, and 24. To find the sum of the smallest three of the five integers, add together the 20, 21, and 22.