Question

How many grams of water can be vaporized with 6500 J of energy? The heat of

vaporization for water is 2330 J/g.

Answer 1

Given :

The heat of vaporization for water is 2330 J/g.

To Find :

How many grams of water can be vaporized with 6500 J of energy.

Solution :

It is given that heat of vaporization for water is 2330 J/g.

Means 2300 J of heat is required to vaporize 1 g of water .

Let , n grams of water is produced by 6500 J of energy .

`n=(6500\ J)/(2330\ J/g)\\\\n=2.79\ g`

Therefore, 2.79 g of water will vaporize by 6500 J of energy .

Hence, this is the required solution .